Print range of numbers

Shell Programming and Scripting
1

Hi

I am getting an argument which specifies the range of numbers. eg: 7-15

Is there a way that i can easily (avoiding loop) print the range of number between and including the specified above.

The above example should translate to 7,8,9,10,11,12,13,14,15

2

Hello tostay2003,

Please use code tags while using commands and codes in your post as per forum rules. Following may help you in same.

for i in {7..15..1}
do
echo "Value of i is $i"
done

Output will be as follows.

Value of i is 7
Value of i is 8
Value of i is 9
Value of i is 10
Value of i is 11
Value of i is 12
Value of i is 13
Value of i is 14
Value of i is 15

Thanks,
R. Singh

3 
$ seq -s, 7 15

---------- Post updated at 05:40 PM ---------- Previous update was at 05:31 PM ----------

If you have the literal value 7-15 as basis and it's in a variable:

$ var=7-15
$ seq -s, `echo $var | tr '-' ' '`
4

With recent shells with brace expansion:

var=7-15
eval echo {${var/-/..}}
7 8 9 10 11 12 13 14 15

The usual caveats for using eval apply.

1 Like