Print Pattern from file

cat file | awk '{printf"(t.who = "'"%s",$1}'

Regards
ADI

awk '{print "(t.who = \x27" $1 "\x27 and trunc(ymddate) = to_date(\x27" $7"-"$8"-"$NF"\x27,\x27mon-dd-yyyy\x27)) or"}' file
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