Print only word not number

Shell Programming and Scripting
1

Hi,

Need to extract only words not numbers

#cat test.txt
123456
oracle
web
56789
s21adm

Required output

#grep <options> test.txt
oracle
web
s21adm

Note, in between integer "s21adm" is required but not with full integer "123456" and "56789"

Any help? I am using AIX Ksh.

Regards,
Siva

3 
awk '!/^[0-9]+$/' test.txt
oracle
web
s21adm
4

try also:

sed -n '/^[0-9][0-9]*$/!p' test.txt
awk '!($0+0)' test.txt
grep -v "^[0-9][0-9]*$" test.txt
5

All of these solutions require processing (beyond simple reading) the entire line. It would be simpler to look for the first non-numeric, or, depending on the OP's needs, the more restrictive first alphabetic character.

grep '[^[:digit:]]' file
grep '[[:alpha:]]' file

Regards,
Alister

6

@Rdrtx1

awk '!($0+0)'

This fail if value of line is 0

Why use [0-9][0-9]* (one digit + 0 or more digit), when you can use [0-9]+ (one or more digit)

7

Why use awk, grep, or sed when it can all be done with ksh built-ins:

while IFS="" read x
do      if [ "$x" != "${x%*[!0-9]*}" ]
        then    printf "%s\n" "$x"
        fi
done < test.txt

It would take a fairly large input file to make the invocation costs of starting up an external binary less expensive than the costs of running this simple loop in the shell.

Note that the problem statement is not clear about what should happen if an input line is a blank line. If blank lines are possible in the input, the specification needs to be extended to state what should happen in this case. The while loop above will print non-empty blank lines, but will not print empty lines.

PS Jotne:

What you suggested will work with:

grep -E '[0-9]+'

which uses extended regular expressions, but not with:

grep '[0-9]+'

which uses basic regular expressions.
This last grep command above will only print lines that contain a digit immediately followed by a plus sign.

8

One reason would be human readability.

The equivalent grep '[^0-9]' test.txt is instantly understandable, while that while-loop takes some time to digest.

Another reason is that the simpler the code the fewer the opportunities for surprises. Your while-loop, for example, would behave badly if there are backslashes in the data (the OP made no assurance against this possibility).

If I were going to do this with sh builtins, I would use case . To me it's more obvious.

case $x in
*[!0-9]*) printf '%s\n' "$x"
esac

Perhaps, but I would categorize that under premature optimization.

Regards,
Alister