print next word after found pattern

Shell Programming and Scripting
1

Hi all,

I'd like to print the next word after a found pattern.

example text:

word1 word2 word3 word4 pattern word5

pattern word1 word2 word3 word4

word1 word2 pattern word4

basiclly the word after pattern.

Thanks

2

What happens when the pattern is last on the line?

3

it never is

4

Try this:

awk '{for(i=1;i<=NF;i++)if($i~/pattern/)print $(i+1)}' infile
1 Like
5

perfect thanks

6

i have a similar situation and i thought i'd drop my question here...

i have a file like below. how to printout the digits followed by the pattern -bwout and -bwin. say i run the script by entering line number 145 (the fourth line), then the o/p should be like
5000000 1024000

8 test1 -ipprot erp -ppsout 500 -ppsin 500 -bwout 300000 -bwin 300000 -statsdevice test1 -stats 
30 test2 -addr a.b.c.249 -wdwthresh 3 -bwout 512000 -bwin 512000 -statsdevice test2 -stats 
125 test3 -addr a.b.c.0 -addrmsk 255.255.255.0 -bwlink total1 -statsdevice testing3 -stats -global 
145 test4 -group -bwout 1024000 -bwin 5000000 -statsdevice group4 -stats 
1451 test5 -addr a.b.c.251 -bwout 256000 -bwin 512000 -bwlink test4 -statsdevice test5 -stats 
14539 test6 -addr a.b.c.34 -bwboth 128000 -bwlink xyz128 -statsdevice abc123 -stats

did i make myself clear?

tia

7

Please do not Bump posts as it's not allowed in the forum. Request you to open a new thread.Thanks!

8 
awk -v var=145 '$1==var {for(i=1;i<=NF;i++) {if($i=="-bwout") print $(i+3),$(i+1)}}' file
5000000 1024000
9 
echo "Enter the line number";read num; awk -v line=$num '{if($1==line){for(i=1;i<=NF;i++){if($i ~ /-bwout/)x=$(i+1);if($i ~ /-bwin/)y=$(i+1);}}} END{print y" "x;}' file

file will have the contents you pasted.

1 Like
10

thank you all