print lines with exact pattern match

Shell Programming and Scripting
1

I have in a file

domain.com. 1909 IN A 1.22.33.44
domain.com. 1909 IN A 22.33.44.55
ns1.domain.com. 1699 IN A 33.44.55.66
ns2.domain.com. 1806 IN A 77.77.66.66

I need to "grep" or "awk" out the lines starting with domain.com. as follows.

 domain.com. 1909 IN A 1.22.33.44
 domain.com. 1909 IN A 22.33.44.55
2 
grep "^domain.com" file
3

Hi,
Try this,

awk '$0 ~ /^domain.com/{print;}' file

Cheers,
Ranga:-)

4 
awk -v v="domain.com." '$1==v' file