print lines which match multiple patterns

Shell Programming and Scripting
1

Hi,

I have a text file as follows:

11:38:11.054 run1_rdseq    avg_2-5 999988.0000  1024.0000   
11:50:52.053 run3_rdrand    999988.0000   1135.0 128.0417   
11:53:18.050 run4_wrrand    avg_2-5 999988.0000  8180.5833
11:55:42.051 run4_wrrand    avg_2-5 999988.0000   213.8333
11:55:06.053 run4_wrrand    999988.0000   9807 510.2083

I have a variable $run, that contains all the unique values of column 2. I need to print lines that match $run and the pattern 'avg'. So from the above text file I would want to print :

11:38:11.054 run1_rdseq    avg_2-5 999988.0000  1024.0000   
11:53:18.050 run4_wrrand    avg_2-5 999988.0000  8180.5833
11:55:42.051 run4_wrrand    avg_2-5 999988.0000   213.8333

If I do something like :

egrep -e '(run4_wrrand.*avg)' textfile.txt

, I get the right output. But if I do:

egrep -e '($run.*avg)' flatfile.html

I get no output. I know shell variables can not be used in this way, but how else can I achieve the above output?

Thanks
Anna

2

Hi,

try:

run=run
egrep -e "$run.*avg" file

HTH Chris

1 Like
3

Wow!!! I had been scrating my head for a couple of hrs on this and all that was needed to fix this was the double quotes!!!!. Thanks a ton Chris!!!!