Print in single line

Shell Programming and Scripting
1

HI
I am having a flle like below .

test.txt

 
ssh aaaaaaa@bbbbbbbbb "head -1 /xxxxxx/yyyyyyy/yyyyyyy.sp.issuer_upd_fd"
echo /xxxxxx/yyyyyyy/yyyyyyy.sp.issuer_upd_fd
ssh aaaaaaa@bbbbbbbbb "head -1 /xxxxxx/yyyyyyy/yyyyyyy.sp.xreff_upd_gm"
echo /xxxxxx/yyyyyyy/yyyyyyy.sp.xreff_upd_gm

when i do

 
sh test > result3

i am getting out put created as follows

IMAHDR cccccc01 ISSUER 20130418 20130418 001
/xxxxxx/yyyyyyy/yyyyyyy.sp.issuer_upd_fd
IMAHDR cccccc01 XREFF 20130228 20130228 001
/xxxxxx/yyyyyyy/yyyyyyy.sp.xreff_upd_gm

BUt i want first 2 command output in one single line .something like the following

 
IMAHDR cccccc01 ISSUER 20130418 20130418 001 /xxxxxx/yyyyyyy/yyyyyyy.sp.issuer_upd_fd
IMAHDR cccccc01 XREFF 20130228 20130228 001 /xxxxxx/yyyyyyyyyyyyyy.sp.xreff_upd_gm
2 
ssh aaaaaaa@bbbbbbb "head -1 /xxxxxx/yyyyyyy/yyyyyyy.sp.issuer_upd_fd | xargs printf %s" && echo " /xxxxxx/yyyyyyy/yyyyyyy.sp.issuer_upd_fd"
3

This is one way:

rv1=`ssh aaaaaaa@bbbbbbbbb "head -1 /xxxxxx/yyyyyyy/yyyyyyy.sp.issuer_upd_fd"`
rv2=`ssh aaaaaaa@bbbbbbbbb "head -1 /xxxxxx/yyyyyyy/yyyyyyy.sp.xreff_upd_gm"`
echo "$rv1 /xxxxxx/yyyyyyy/yyyyyyy.sp.issuer_upd_fd"
echo "$rv2 /xxxxxx/yyyyyyy/yyyyyyy.sp.xreff_upd_gm"
4 
f1=/xxxxxx/yyyyyyy/yyyyyyy.sp.issuer_upd_fd
f2=/xxxxxx/yyyyyyy/yyyyyyy.sp.xreff_upd_gm
cat << EOF
$(ssh aaaaaaa@bbbbbbbbb "head -1 $f1") $f1
$(ssh aaaaaaa@bbbbbbbbb "head -1 $f2") $f2
EOF

or

f1=/xxxxxx/yyyyyyy/yyyyyyy.sp.issuer_upd_fd
f2=/xxxxxx/yyyyyyy/yyyyyyy.sp.xreff_upd_gm
printf "%s\n" "$(ssh aaaaaaa@bbbbbbbbb "head -1 $f1") $f1"
printf "%s\n" "$(ssh aaaaaaa@bbbbbbbbb "head -1 $f2") $f2"