please help me in FreeBSD

UNIX BSD
1

Hi to all,

Iam doing a project in Free BSD and i am stuck with a puzzle. Please any one of you clarify my doubt :

How to add a mechanism to check the status of the file system which alerts the root user via. email if any single partition is greater than 90% full. This alert should include the file system directory name and the partition?
:confused:

2

Iam working on Free BSD 5.3 version. U all know that the output of 'df' command looks as follows:

Filesystem 1K-blocks Used Avail Capacity Mounted on
/dev/ad0s1a 253678 59116 174268 25% /
devfs 1 1 0 100% /dev
/dev/ad0s1e 253678 24280 209104 10% /tmp
/dev/ad0s1f 8913022 2615376 5584606 32% /usr
/dev/ad0s1d 253678 30246 203138 13% /var
devfs 1 1 0 100% /var/named/dev

Now i want to check which partition if greater than 90% full without scanning the first row of record. How to do this ? PLease anyone of u help me with this?

3

I'm not a regular BSD user, but this can be done in a shell script using "cut"

look up the man page for "cut" and you should immediately see how you can use it to parse the output of df

4

This is quick, done early in the morning, but it works. Please don't yell at my 'inefficiencies" ! :>D Streamline it as you will.
It more than likely NEEDS it BADLY.

#!/bin/ksh

get_size () {

IFS="%
"
df -k | grep '\/dev\/' | awk '{ printf "%s\t%d\n",$6,$5 }'

IFS="
"

}

alm_func () {
LIM=$1
shift
NUM=`echo $#/2 | bc`
while [ $NUM -gt 0 ]
doif [ $2 -gt $LIM ]; then

[INDENT]echo "Partition $1 is at $2'%'."
fi
shift;
shift;
((NUM=NUM-1))
done[/INDENT]
}

#=======

if [ $# -ne 1 ]; then
echo "$0: Invalid number of arguments"
echo "usage: $0 <filesystem utilization limit>"
exit 1
fi

LIMIT=$1

alm_func $LIMIT `get_size`

======
IFS is usually "<space><tab><\n>" I add the '%'
as a lazy way to make it a field delimiter and 'subtract' it from the 'df -k' output. Dirty, I know. :>D

==
If you want the DEVICE name, substitute '$1' for the '$6' in the AWK statement in "get_size()"

====