Piping output from a command into bash script

Shell Programming and Scripting
1

Hi all. I am using procmail to deliver an email to a script I am developing. Procmail delivers the email to the script on standard input. I imagine this is the same as piping input from a command into the script. Hence I've been testing my script by running
echo 'test' | sms-autosend-backup.sh

I would expect the script to echo out the input passed to it, but this does not happen, I just get a blank line. My question is, how do I store standard input in a variable in my script? Is $1 not correct? Script is below. Thanks!

#!/bin/bash -norc

message=$1
echo $message

My .procmailrc looks like this:

VERBOSE=off
HOME=/home/sms-dev
MAILDIR=/var/spool/mail/sms-dev
LOGFILE=$HOME/procmail.log
SH=/bin/sh
PATH=/bin:/usr/bin:/usr/local/bin

:0
* ^TOsms-dev@sms.sms.local
{
:0c
| /home/sms-dev/sms-autosend.sh
:0
/var/spool/mail/sms-dev
:0
/home/sms-dev/mboxtest
}
2

are you passing test as a $1 to your script sms-autosent-backup.sh if yes then you should be executing the script like ---------

sms-autosend-backup.sh  test
3

$1 is the 1st arg of command line of script invocation.
Try using bash's read command since it is input.