piping ls to zenity and returning selection to variable

Shell Programming and Scripting
1

Hi

I'm fairly new to unix and scripting (in BASH) and am here to post my first question.

What I'm trying to do is pipe a sorted listing (ls) to zenity and when the list appears to the user, the choice they choose is returned to a variable so it can be used in conditional statements.

I can get the list to appear but not get the choice. Example i'm using below:

Say my PWD has directories/files 'one' and 'two':

ls|sort|zenity --list --title="whatever" --column="thing"

This will show 'one' and 'two' in a list, and when one is selected and ok pressed, the selection is echoed into the terminal. I want it to be stored in a variable instead.

Any ideas?

Thanks

2

Use command substitution:

x=$( ls|sort|zenity --list --title="whatever" --column="thing" )
1 Like
3

Yeah that works fine. Thanks.

Should have thought of that earlier since I tried:

x=(ls|sort|zenity --list --title="whatever" --column="thing")

Was only missing the $

Ah well. Thanks again.