Pattern matching first occurance only wanted

Shell Programming and Scripting
1

I have the following code:

declare -a search
search=(name label elapsed totalfilecount totalfilebytes starttime exitcode errors warnings fatals)
for (( i = 0 ; i < ${#search[@]} ; i++ ))
do
        data=`awk -F '^'${search[$i]}'=\"' 'BEGIN{RS="\" "; OFS="\n"; ORS=""} { print $2 }' summary.alg`
        echo "${search[$i]}: $data"
done

it scans through alog file like this:

name="myserver01" label="ashburn_daily-ash_hpux-1228953600121" excluded="0" dirbytes_sent="2144078"
 dirbytes_hashcache="13155171" filebytes_ispresent="26919788" compbytes_ispresent="15160" 
 filebytes_sent="7524448242" filebytes_skipped="0" totalprimarybytes="1375375088179" dirbytes_ispresent="1728" 
 compbytes_sent="23386944" filebytes_hardlink="430957859" chunkcount_hashcache="3231729" errors="0"
 warnings="0" fatals=""

In the log file it scans there is, for some unknown reason, duplicates of some of the data.
The script I have will pull all of the matching data.

So if name="myserver01" ..Blah.Blah.. name="myserver01" it will out put the data twice.
How do I change the following to only return the first occurance.

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 data=`awk -F ${search[$i]}'=\"' 'BEGIN{RS="\" "; OFS="\n"; ORS=""} { print $2 }' summary.alg`
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2

Please reformat your post so that the lines fit within a typical browser window.

For code the usual maximum line length is something less than 80 characters.

The way it is now, it is too hard to read, and few people will bother scrolling sideways on every line in order to read it.