Passing parameters and accepting in Array

UNIX for Beginners Q & A
1

I am trying to pass parameters to a script which will accept them in array.

First parameter is where_clause
second parameter is "SRC_TYPE='SYBASE' and PROCESS_CD='BRK'"

[$ cat abcd.ksh
set -x
set -A arg_list -- $*
echo ${arg_list[1]}
echo $2
$  ./abcd.ksh where_clause "SRC_TYPE='SYBASE' and PROCESS_CD='BRK'"
+ set -A arg_list -- where_clause SRC_TYPE=$'\'SYBASE\'' and PROCESS_CD=$'\'BRK\''
+ echo SRC_TYPE=$'\'SYBASE\''
SRC_TYPE='SYBASE'
+ echo SRC_TYPE=$'\'SYBASE\'' and PROCESS_CD=$'\'BRK\''
SRC_TYPE='SYBASE' and PROCESS_CD='BRK'

When echoing $1 $2 etc , it displays correctly, But when assigned to an array it splits the parameters with space.
Can some one help me to modify the code to assign the second variable with single quotes and spaces as the second element of the array

--- Post updated at 04:35 PM ---

Found the solution after more research. Pasting here for reference
used

set -A arg_list -- "$@"

instead of

set -A arg_list -- $*

Out put looks like below

 ./abcd.ksh where_clause "SRC_TYPE='SYBASE' and PROCESS_CD='BRK'"
+ set -A arg_list -- where_clause SRC_TYPE=$'\'SYBASE\' and PROCESS_CD=\'BRK\''
+ echo SRC_TYPE=$'\'SYBASE\'' and PROCESS_CD=$'\'BRK\''
SRC_TYPE='SYBASE' and PROCESS_CD='BRK'
+ echo SRC_TYPE=$'\'SYBASE\'' and PROCESS_CD=$'\'BRK\''
SRC_TYPE='SYBASE' and PROCESS_CD='BRK'
2

Not sure if this is helpful:

AMIGA:amiga~> echo SRC_TYPE=$"'"SYBASE"'"" and PROCESS_CD="$"'"BRK"'"
SRC_TYPE='SYBASE' and PROCESS_CD='BRK'

--- Post updated at 10:03 PM ---

3

Use "$@" instead of $* quotes and all. That will guarantee it splits on arguments only and not spaces.

4

Yes, use the @ index and put the $expression in "quotes" to split on elements and not on embedded whitespace.
Further examples:

printf "%s\n" "$@"

printf "%s\n" "${arg_list[@]}"

for arg in "$@"; do ...

Or its short form

for arg
do ...

for arg in "${arg_list[@]}"
do ...