Passing awk variables to shell

Shell Programming and Scripting
1

Hi.
I need to parse file and assign some values to variables, right now i do like below

MYHOMEDIR=`awk '/Home/ {print $NF}' output.txt`
MYSHELL=`awk '/Shell/ {print $NF}' output.txt`
PRGRP=`awk '/Primary/ {print $NF}' output.txt`
SECGRP=`awk '/Second/ {print $NF}' output.txt`

In this case, AFAIK, output.txt is being opened 4 times. This is not good, because output.txt could be quite large. I beleive this can be done in one query. Pls assist.

2

Save below code as 'var.sh' and chmod 755 var.sh

#! /bin/sh
awk '
  /Home/    { v="MYHOMEDIR";printf("%s=%s;export %s\n",v,$NF,v) }
  /Shell/   { v="MYSHELL";printf("%s=%s;export %s\n",v,$NF,v) }
  /Primary/ { v="PRGRP";printf("%s=%s;export %s\n",v,$NF,v) }
  /Second/  { v="SECGP";printf("%s=%s;export %s\n",v,$NF,v) }
' output.txt

You need to get the shell to do two parses before execution using 'eval'

eval `./var.sh`
3

I have assigned first column as the variable name ..

$ awk '/(Home|Shell|Primary|Second)/ {print $1"="$NF}' infile > infile1

$ chmod 755 infile1

$ . ./infile1
 
$ echo $Home $Shell $Primary $Second
2 3 4 6
1 Like
4

Another way ....

set $(awk '/Home/ { home=$NF }
     /Shell/ { shell=$NF }
     /Primary/ { primary=$NF }
     /Second/ { second=$NF }
     END { print home, shell, primary, second }' infile)

MYHOMEDIR=$1; MYSHELL=$2; PRGRP=$3; SECGRP=$4;

echo $MYHOMEDIR
echo $MYSHELL
echo $PRGRP
echo $SECGRP
5

Cool, but it is not working if i use ":" as filed separator and values with spaces. How to resolve this?

6

Provide some input file contents and expected output ..

7

Input file:

    Account Owner     : me
        Description       : me myself
        Login               : mylogin
        ID                   : 43303993
        Application       : test
        UID Number        : 3017256
        Password          : (encrypted)ololo
        Primary Group     : (451) testunix
        Secondary Group   : dialer wheel webgroup
        Home Directory    : /home/me
        Login Shell       : /usr/bin/ksh

I want to assign to variables value of fields "Primary Group" "Secondary Group" "Home Directory" "Login Shell". "Secondary Group" value could contain spaces

8

Please try to post the actual sample to save time.
You must remove the spaces in LHS to make available in UNIX.

eval $(awk -F: '/(Primary Group|Secondary Group|Home Directory|Login Shell)/ {gsub(/[ ][ ]*/,"",$1);print $1"=\""$2"\""}' file)

$ echo $PrimaryGroup
(451) testunix
$ echo $SecondaryGroup
dialer wheel webgroup
$ echo $HomeDirectory
/home/me
$ echo $LoginShell
/usr/bin/ksh
$
9

It is not working for me

testhost$ eval $(awk -F: '/(Primary Group|Secondary Group|Home Directory|Login Shell)/ {gsub(/[ ][ ]*/,"",$1);print $1"=\""$2"\""}' output)
awk: syntax error near line 1
awk: illegal statement near line 1
testhost$ uname -a
SunOS testhost 5.8 Generic_117350-46 sun4u sparc SUNW,Sun-Fire-V240
10

use nawk

1 Like
11

Many thanks