passing awk variable to the shell script

hi;

i have a file containing lines like:

1|1069108123|96393669788|00963215755711|2|0|941||;serv:Pps6aSyria;first:0;bear

i want to extract the second, third and fourth record of each line and store it in a file ";" seperated

this is what i wrote

while read line
do
A_party=`echo $line |awk -F["|"] '{print $3}'`
B_party=`echo $line |awk -F["|"] '{print $4}'`
time=`echo $line |awk -F["|"] '{print $2}'`

            echo $A\_party";"$B_party";"$time >> $_outfile
    done < $_infile 

But the problem is that i am calling three times awk for each line, how can i pass awk variable to the script in order to call awk only one time.

Thanks in advance.

An awk one liner should do the trick for the whole set of data

awk -F'|' '{printf( "%s;%s;%s\n", $2, $3, $4 ) >> "outfile" }' infile

Cheers
ZB

Or

awk 'BEGIN{FS="|";OFS=";"}{print $2,$3,$4}' infile > outfile

Thanks a lot both worked fine.

question, how can i pass let's say $2 to the script in case i will need it in other place of the script.
remember the subject of my thread.

thanks a lot for your help guys.