Passing an argument to cut command

Shell Programming and Scripting
1

Can we pass an argument to cut command as below

Suppose cut command is used in for or while loop and we need to pass the incremental counter

cut -f$i

Here $i is an argument.

Like wise it has to come

cut -f1
cut -f2

Where i=1,2,3,....

2

As a general rule when wondering if a given construct works, try it and see what happens :wink: , (NB: does not apply to potentially destructive commands)

for i in $(seq 10) ; do echo cut -d\, -f$i tmp.csv ; done
cut -d, -f1 tmp.csv
cut -d, -f2 tmp.csv
cut -d, -f3 tmp.csv
cut -d, -f4 tmp.csv
cut -d, -f5 tmp.csv
cut -d, -f6 tmp.csv
cut -d, -f7 tmp.csv
cut -d, -f8 tmp.csv
cut -d, -f9 tmp.csv
cut -d, -f10 tmp.csv

Looks good to me...