Parsing records in file

Shell Programming and Scripting
1

have a datafile that contains:

Jun 13 12:59:21
Jun 13 13:02:04
Jun 13 13:14:21

i want to parse this so they look like this:

Jun 13 12:59
Jun 13 13:02
Jun 13 13:14

how can i do this? basically wanna get rid of the seconds.

i'd prefer this to be a one liner.

command | awk blah blah

shell: bash

3

Please post sample data for a single digit day.

5

the date format is exactly the same as that of the unix messages file.

meaning:

Jun  8 13:02:04
Jun 10 14:05:98

notice the two spaces in the single digit date

6 
$ awk -F: 'sub(FS $NF,z)' file
Jun 13 12:59
Jun 13 13:02
Jun 13 13:14
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8 
cut -c-12 file

colrm 13 <file
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