Parsing a timestamp until EOF

Shell Programming and Scripting
1

hey guys, i'm having a bit of trouble with my script. based on the time you started a shift for work, it's supposed to read the input, and then parse a log file of alerts accordingly. my issue is parsing out from the time entered as your start time until the end of the file. the format looks like this

09-21-2010 05:14:23
09-21-2010 06:25:23
09-21-2010 07:47:23
09-21-2010 08:45:23
09-21-2010 09:34:23
09-21-2010 10:10:23

so if my time started is at 7am. i'd want it to parse the file for 7am all the way down until the EOF. any help on this would be appreciated, thanks!

2

You could do something like this:

$ sed '/^09-21-2010 07/,$!d' infile
09-21-2010 07:47:23
09-21-2010 08:45:23
09-21-2010 09:34:23
09-21-2010 10:10:23

or

sed -n '/^09-21-2010 07/,$p' infile

which is equivalent..

3

two things, one I would be running this on different days, and months, and two im going to have the time started as a variable that is taken from user input. so it will initially prompt me what time i started, then read the input and create a variable. so essentially my variable for $SHIFT would be 7 for this example. so something like this maybe..?

sed -n '/^$SHIFT/,$p'
4

You would need to use double quotes to let the shell expand $SHIFT

sed -n "/^$SHIFT/,$p"
5

okay, thanks. i'll tinker with that and try to get it working.:slight_smile:

6 
D="09-21-2010"
T="07"

Or 

D=$(date +%m-%d-%Y)
T=$(date +%H)

awk -v date=$D -v time=$T '{split($2,a,":")} $1==date&&a[1]>=time' infile
1 Like
7

awesome, thanks alot. this works perfect!:slight_smile: i just changed the variable $T to my variable $SHIFT for hour started and it works. lol