Output sftp to log file

Shell Programming and Scripting
1

Dear Sirs,

would like to seek advise.
how to log the sftp output.

#!/usr/bin/bash
Date='date +%Y%m%d'
mkdir -p "/appl/scripts/ftp/logs/ftp-$Date"
LOGFILE=/appl/scripts/ftp/logs/ftp-$Date
while read -r server2
do 
sftp etpuser@"$server2" << "_EOSFTP_"
cd /test2
lcd /test3
mget * >> $LOGFILE
done
_EOSFTP_
done < server2

i tried to run the script, i m getting error
Multiple source paths, but destination ">>" is not a directory
Invalid command.
sftp> done

thank yousss Sirs

2

Please use some code validator for your shell scripts, e.g. ShellCheck.net

#!/usr/bin/env bash
Date=$(date +'%Y%m%d')
mkdir -p "/appl/scripts/ftp/logs/"
LOGFILE=/appl/scripts/ftp/logs/ftp-"$Date"
while read -r server_name
do 
  sftp etpuser@"$server_name" << "_EOSFTP_"
cd /test2
lcd /test3
mget *
_EOSFTP_
done < server2 >> "$LOGFILE"
1 Like
3

Dear Sirs,
i have tried to ammend , forg8 comments.

#!/usr/bin/bash
Date='date +%Y%m%d'
mkdir -p "/appl/scripts/ftp/logs/ftp-$Date"
cd /appl/scripts/ftp/logs/ftp-"$Date" || exit
while read -r server2
do 
sftp etpuser@"$server2" > ftp-"$Date" << "_EOSFTP_"
cd /test2
lcd /test3
mget * 
done
_EOSFTP_
done < server2

thank youssss Sirs

4

This is not the code I posted above. Anyway...

Date='date +%Y%m%d' this line will not work, because single quote ' is not backtick `, so this is incorrect syntax for command substitution.

sftp etpuser@"$server2" > ftp-"$Date" << "_EOSFTP_" this line will constantly overwrite the file ftp-"$Date", as redirection is not an appending one (apart from Date variable not storing the correct value, see above).

Is your input data file named server2? Does it contain valid hostnames/IP addresses?

3 Likes
5

thank yousss so much Sir for g8 expertise. truly appreciate it.