output required

Shell Programming and Scripting
1

Hi

I have the following output

Message man amm (9196) is calling
Hello & Alert man amtrr (9197) is stopped
Find amfi (19198) is cancelled
Engine Item aea (19203) is notified
Engine Item2 aea2 (19204) is notified

I need to print only the column which contains amm,amtrr,amfi,aea & aea2

in awk $3 does not give 3rd line i.e amfi.... The clue is the items i need to print starts with 'a'

2

Assuming the pattern is always before the field between the parentheses:

sed 's/.* \(.*\) (.*/\1/' file
3

no,

I do have brackets before the pattern

4

That's what I mean, have you tried the command?

5

i also have down the file like

Req Har omrh (2254) is terminating
MR Rect (MRRT) omrrt (2255) is concluding
DR Rect (DRRT) omrdt (2256) is concluding

6

Have you tried the command?

7

yes, the first half of the output is empty and then one line with the correct word printed and the blank output.

In simple terms, I need to print the word which starts with a letter 'o' for each line.

<---Only one word in each line which starts with letter 'o' . That word could be anywhere in the line i.e $1 or $2 or $3 or $4--->

8 
awk '{for(i=1;i<=NF;i++){if($i ~ "^o"){print $i}}}' file
9

worked fine. Thanks Franklin.