Output not coming as desired.

Shell Programming and Scripting
1

Hi guys.

I have a file containing some hosts and their IPs.

host host1 192.168.2.10
host host2 192.168.2.11
host host3 192.168.2.12

I am writing a script where I want to print these values in 1 line. My script looks like

RUNTIME_NODE=`cat hosts.properties | grep host`

for i in $RUNTIME_NODE
do
        echo $i | awk '{ print $1  $2 $3 }'
done

The output I am expecting is:

host host1 192.168.2.10

host host2 192.168.2.11

host host3 192.168.2.12

But the result I am getting is:

host 
host1 
192.168.2.10
host 
host2 
192.168.2.11
host 
host3 
192.168.2.12

How can I fix this ?

2

To double space the file:

sed G FILE
3

Not quite following,

why not?

grep host hosts.properties | awk '{print $0"\n"}'

or simply

awk '/host/{print $0"\n"}'
4

Why not

 awk '/host/{print $0"\n"}' host.properties

or in sed

 sed '/host/!d;G' host.properties

Of course there is no need to match a pattern if the file only needs double spacing.

5

Hi guys,

The issue is that I have 2 colums and I have to run 1 for loop for comparision purposes.

Column 1 contains

host1
host2
host3

Columns 2 contains

192.168.2.10
192.168.2.11
192.168.2.12

Combined file is:

host1 192.168.2.10
host2 192.168.2.11
host3 192.168.2.12

Now I ahve to run 1 for loop but I need 2 variables under that for loop. One variable takes first column and second variable takes second column RESPECTIVELY.

How can I do that ?

6

comparison of what? did you try the provided solutions?

7

Yes it works. Thanks !

8

Does it?
For your problem in post#5, try

while read X HOST IP
  do echo $HOST $IP
  done < hostfile

and use the variables for your comparisons.