number of digits after decimal

Shell Programming and Scripting
1

Hi All,

I have a file of decimal numbers,

 
cat file1.txt

1.1382666907
1.2603107334
1.6118799297
24.4995857056
494.7632588468
560.7633734425
.....

I want to see the output as only 7 digits after decimal

 
cat output.txt

1.1382667
1.2603107
1.6118799
24.4995857
494.7632589
560.7633734
...

Thanks in advance,

2 
 nawk '{printf("%.7f\n", $1)}'  myFile
OR
nawk '{print $1+0}' OFMT='%.7f'  myFile
1 Like
4 
for line in $(cat file1.txt); do whole=$(echo $line | cut -d. -f1); fraction=$(echo $line | cut -d. -f2 | cut -c 1-7); echo "$whole.$fraction"; done
5

dangerous backticks

6

one more ..

$ while read i;do echo "scale=7;$i/1" | bc;done<infile
7

Move the pipe out of the loop, so you run bc once to process all the data instead of running bc 376 separate times to process 376 lines.

while read i;do echo "scale=7;$i/1" ; done<infile | bc