Number each occurence using sed

Shell Programming and Scripting
1

hi,

I need to number each occurrence of a pattern within a file using sed.

Given

object
0000
object
111
object 
222

I need following

1.object
0000
2.object
111
3.object 
222

Any help would be appreciated.:frowning:

2 
c=1; while read x; do echo $x | grep -q "object";
if [ $? -eq 0 ]; then 
    echo $x | sed "s/^/$c\. /"; c=$(($c + 1)); else echo $x;
fi;
done < input
1 Like
3

Thank you.
Also i need to extract what is in between object one and two.

1.Objec
2222222aaaa
2.Object
222ddddd
3.Object
222ssss

I need
2222222aaaa
then
222ddddd
and so on...

4 
$ nawk 'NR%2==0' infile
5 
grep -v "object" inputfile
6 
nawk '!NR%2' input.txt