Not getting array in .awk file and print it

Shell Programming and Scripting
1

I have test.sh file as below :

set -A IDARR $ID
echo | awk -f test.awk -v TempArr="${IDARR
[*]}"

I have test.awk file as below :

BEGIN {
Flag = 1;
}
{
 print "Hello";
 for(i in TempArr)
 {
  print i;
 }
}

Here script is running fine when I run like test.sh
but not getting output as
Hello and array values....

Please help me what is wrong in the script

2

TempArr is just a variable inside awk, its not an array as you think and trying to iterate through for (i in arr) construct.

What does your $ID contains? May be you can get the array created inside awk itself.

1 Like
3

You need to split the TempArr variable into an awk Array, which then you can iterate through.

1 Like
4

As RudiC said you have to use split function

Here is example to start

$ bashArray=(10 20 30 4 50)

$ cat test.awk 
BEGIN{ 
          split(variable,awkArray); 
          for(i in awkArray)
          print "index="i,"Element="awkArray
     }

$ awk -f test.awk -v variable="${bashArray[*]}"

Resulting

index=4 Element=4
index=5 Element=50
index=1 Element=10
index=2 Element=20
index=3 Element=30
1 Like
5

Thanks Akshay,

Whne I tried as below code, no is giving the 0 value and for that resion not getting any value from array. Please help me on this... :slight_smile:
OUTPUT like :
0
After spliting

but not getting array elements...

        no = split(TempArr, Temp);
        print no;
        print "After spliting";
        for(i in Temp)
        {
                print Temp;
        }
6

Please show your full code. if TempArr is awk variable, and not empty then it should work, before using split , put this print TempArr and check, whether variable is empty or not, if its prints nothing then what you are getting "0" is right. since variable has nothing to split.

7

When I tried to print that values in test.sh file, I am getting 2 values from array

set -A IDARR $ID
echo "${IDARR
[*]}"
echo | awk -f test.awk -v TempArr="${IDARR
[*]}"

Getting out put as below :
3 1

Thanks in advance... :slight_smile:

8

Yes, and what's wrong? What would you expect? Show us the contents of test.awk and IDARR.

9

Here I am getting output from test.sh file not from test.awk file
I wanted that array values from test.sh to test.awk file

10

Use this

$ cat test.ksh
#!/bin/ksh

# some value
ID="1 2 3 4 5 6 7"

# Array
set -A IDARR $ID

# Echo array contents...
echo "From shell ${IDARR[*]}"

# Execute awk script
awk -f test.awk -v TempArr="${IDARR[*]}"

$ cat test.awk
BEGIN {

 # this is variable
 print "from awk", TempArr;

 # split variable contents into array with default FS space
 split(TempArr,NewArray)

 # print contents of NewArray we created above..
 for(i in NewArray)
 {
  print "index",i,"element",NewArray;
 }
}

Resulting

$ ksh test.ksh 
From shell 1 2 3 4 5 6 7
from awk 1 2 3 4 5 6 7
index 4 element 4
index 5 element 5
index 6 element 6
index 7 element 7
index 1 element 1
index 2 element 2
index 3 element 3

From terminal if you want to execute awk script try like this

$ awk -f test.awk -v TempArr="Hai hello world this is test"

Resulting

from awk Hai hello world this is test
index 4 element this
index 5 element is
index 6 element test
index 1 element Hai
index 2 element hello
index 3 element world