Nohup inside shell script

Shell Programming and Scripting
1

Hi,
I want to run another script inside shelll script in nohup mode.
let explain.

under the same folder ,I have two scripts
scrone.sh
scrtwo.sh

In scrone.sh

if [ var -eq 1 ]
then
nohup ./scrtwo.sh &
echo " Script two has been run correctly"
else
echo " Exiting from the script"
fi

If I run the aboce script, it stucks in the nohup , normally we used to to run in command mode. I want to run the scrtwo.sh in nohup , then the control should come out from that and should show the echo command "Script two has been run correctly" .

Please help on this.

2

is scrtwo expecting any input?? Or is it printing anything to stdout??

3

Are you sure scrtwo.sh is executing correctly?
Try redirecting output to some other file say nohup.log instead of default nohup.out

regards,
juzz4fun

4

Hi,
Thanks for your reply.
Both scripts are independent...
I need to run the second script in nohup mode from first script. But when the above code execute, the main script(scrone.sh) is get stuck while executing the scrtwo.sh in nohup . I want to run the scrtwosh then have to to remaining part in the main script.