negate * with in pattren matching...

Shell Programming and Scripting
1

Hi Every one

I have a file in the following manner...

AAAAAAPERFORM WRITEQ
BBDFDDPERFOMF WRITEQ
FFFF *PERFOMF WRITEQ

i want to find the lines which donot have * in 7th position..

I have tried this but some problem i think...

grep '......[^\*][.]*WRITEQ' INpFIle...

any 6 chars not followed by * and any char followed by WRITEQ

but this gets me everyting... including 7th char as *

2

Try this :

grep -v '^......\*.*WRITEQ' infile

Jean-Pierre.

3 
grep '^.\{6\}[^*].*WRITEQ' filename

sed -n '/^.\{6\}[^*].*WRITEQ/p' filename
4

thanks Jean-Pierre, Anbu

It works....

5

Small Help

My inp file is

TSQGN8* MOVE 'WRITEQ ERROR' TO MSG-FIELDO
*
MOVE 1 TO WS-TS-ITEM.
******* CHANGE FOR CICS END*******
EXEC CICS WRITEQ TS QUEUE
ABCD
EFGH
END-EXEC.

I am using the following

awk '/^.\{6\}[^*].* WRITEQ /,/END-EXEC/' InpFile

I wanted to find the line Between WRITEQ and END-EXEC
Provided WRITEQ is no Commented and has one space before and after

the Out put should be

       EXEC CICS WRITEQ TS QUEUE
       ABCD
       EFGH
       END-EXEC.

but i dont now it fails....

6

another way

awk 'BEGIN{FS=""}$7 != "*"' file
7

the following worked...

awk '/^......[^*].*WRITEQ/,/END-EXEC/p' temp

Thanks,,,

8

wrong Question...