Need to put semicolon

Shell Programming and Scripting
1

Hi guys,

I want to write script so that i can put semicolon after every numeric

e.g
input would be like that
50060E80058F49A4

Output should be

50:06:0E:80:05:8F:49:A4

Please help

Thanks & Regards
Nirjhar

2 
#! /bin/bash
while read x
do
    y=''
    while [ ${#x} -gt 0 ]
    do
        y="${y}${x:0:2}:"; x=${x#??}
    done
    echo ${y%?}
done < inputfile

or

sed 's/\(..\)/\1:/g; s/:$//' inputfile
1 Like
3

Thanks for the reply it is properly working with the While loop...
but i want to do it with the sed and it is not giveing the right output...

I have little bit idea of sed,it would be great if u can explain the little......so i can modify the same acording to my need..

Thanks
Nirjhar

4

or try like this

# sed 's/../&:/g;s/.$//'
5

Thanks for the reply again but i am getting the minor mistake....

5:00:60:E8:00:58:F4:90: it is coming like that......:frowning:

6

what is your code and inputfile?

7

The input file is

50060E80058F4900
50060E80058F4920
50060E80058F4901
50060E80058F4921
50060E80058F4904
50060E80058F4924
50060E80058F4905
50060E80058F4925
50060E80058F4984
50060E80058F49A4
50060E80058F4985
50060E80058F49A5
50060E80058F4910
50060E80058F4930
50060E80058F4911
50060E80058F4931
50060E80058F4914
50060E80058F4934
50060E80058F4915
50060E80058F4935
50060E80058F4994
50060E80058F49B4
50060E80058F4995
50060E80058F49B5

8

This works:

$ sed 's/\(..\)/\1:/g; s/:$//' inputfile
50:06:0E:80:05:8F:49:00
50:06:0E:80:05:8F:49:20
50:06:0E:80:05:8F:49:01
50:06:0E:80:05:8F:49:21
50:06:0E:80:05:8F:49:04
50:06:0E:80:05:8F:49:24
50:06:0E:80:05:8F:49:05
50:06:0E:80:05:8F:49:25
50:06:0E:80:05:8F:49:84
50:06:0E:80:05:8F:49:A4
50:06:0E:80:05:8F:49:85
50:06:0E:80:05:8F:49:A5
50:06:0E:80:05:8F:49:10
50:06:0E:80:05:8F:49:30
50:06:0E:80:05:8F:49:11
50:06:0E:80:05:8F:49:31
50:06:0E:80:05:8F:49:14
50:06:0E:80:05:8F:49:34
50:06:0E:80:05:8F:49:15
50:06:0E:80:05:8F:49:35
50:06:0E:80:05:8F:49:94
50:06:0E:80:05:8F:49:B4
50:06:0E:80:05:8F:49:95
50:06:0E:80:05:8F:49:B5
9

what is your desired output?
is that or ?

# sed 's/../&:/g;s/.$//' file
50:06:0E:80:05:8F:49:00
50:06:0E:80:05:8F:49:20
50:06:0E:80:05:8F:49:01
50:06:0E:80:05:8F:49:21
50:06:0E:80:05:8F:49:04
50:06:0E:80:05:8F:49:24
50:06:0E:80:05:8F:49:05
50:06:0E:80:05:8F:49:25
50:06:0E:80:05:8F:49:84
50:06:0E:80:05:8F:49:A4
50:06:0E:80:05:8F:49:85
50:06:0E:80:05:8F:49:A5
50:06:0E:80:05:8F:49:10
50:06:0E:80:05:8F:49:30
50:06:0E:80:05:8F:49:11
50:06:0E:80:05:8F:49:31
50:06:0E:80:05:8F:49:14
50:06:0E:80:05:8F:49:34
50:06:0E:80:05:8F:49:15
50:06:0E:80:05:8F:49:35
50:06:0E:80:05:8F:49:94
50:06:0E:80:05:8F:49:B4
50:06:0E:80:05:8F:49:95
50:06:0E:80:05:8F:49:B5
1 Like
10

Hi ygemici,

Thanks for the response, I got the desired o/p.

I have also try to under stand ur code.....
sed 's/\(..\)/\1:/g; s/:$//'

i got all the things but can you tell me what is the use \1 here.
i did n't get this concept, i have tried it without \1 but than its not taking the input file.

Hope you will answer.

Regards
Nirjhar

11

\1 is back reference to the sub-pattern in first parenthesis of the pattern. In this case, \(..\) is the sub pattern in first parenthesis. This is referred by \1.

1 Like
12

Thanks for the reply. I got the idea here we use /1 to store the pattern inside it. and we can store up to 9 patterns.