Need to grep 2 words from Perl Script results in Terminal....

Shell Programming and Scripting
1

Hey guys. I have a .pl script that scans my hosts to see if they are down or up. I can run it anytime I want. The script uses a conf file that contains text lines of the IP addresses of the servers. I run the script from the command line of my terminal (MAC OS)

I run:

sudo ./scanner.pl

brings back:

10.0.1.1 - DOWN

10.0.1.2 - DOWN

10.0.2.3 - UP

10.0.2.4 - DOWN

10.0.3.5 - UP

10.0.3.6 - UP

I want to only have displayed for me the results of the two xx.x.3.x results

but if I run this:

sudo ./scanner.pl | grep 3

OR

sudo ./scanner.pl | grep UP

then I get this:

10.0.2.3 - UP

10.0.3.5 - UP

10.0.3.6 - UP

But I only care about the last 2 results (3.5 and 3.6)

so I tried:

sudo ./scanner.pl | grep UP 3.
hoping that it would be able to grab the lines that have both of those parameters, but that doesnt work....

How do I specify 2 things to grab from one line?

For Example, I only want to display:

10.0.3.5 - UP

10.0.3.6 - UP

THANKS IN ADVANCE

2 
sudo ./scanner.pl | perl -wlne '/\d+.\d+.3.\d+.*/ and print ;'

;);):wink:

3 
sudo ./scanner.pl | awk -F. '$3==3'
4

By using a regex that has both the search patterns in each line.

$
$ ./scanner.pl
10.0.1.1 - DOWN

10.0.1.2 - DOWN

10.0.2.3 - UP

10.0.2.4 - DOWN

10.0.3.5 - UP

10.0.3.6 - UP

$
$ ./scanner.pl | grep "3.[56] - UP"
10.0.3.5 - UP
10.0.3.6 - UP
$
$

tyler_durden