while(EOF != (c = fgetc(filePtr)))
{
if ((c == ' ') || (c == '\n') || (c == '\0'))
{
if (c == '\0')
{
continue;
}
printf("%s",cc);
printf("%c\n");
memset(cc, 0, sizeof cc);
}
else
{
cc=c;
i++;
}
I supposed from that code to print word by word from text file but there is something wrong with <<<<memset(cc, 0, sizeof cc);>>>>>
it give me like that
Post your entire code. From the look of those warnings, there may be a problem with the way you declared your variables.
You also don't ever null-terminate your array, putting a '\0' as the last character, so printf and anything else that uses strings won't know where it ends.
ok thank you all in advance I forgot to put i=0;
to start from the first location of char array but any way can anyone help me with that little freaky symble at the end of the word
while(EOF != (c = fgetc(filePtr)))
{
if ((c == ' ') || (c == '\n') || (c == '\0'))
{
if (c == '\0')
{
continue;
}
printf("%s",cc);
printf("%c\n");
i=0;
memset(cc, 0, sizeof cc);
}
else
{
cc=c;
i++;
}
Post your entire code.
What is this for?
printf("%c\n");
%c means 'print one character that I passesd as an argument' but you passed no argument. It's going to print whatever garbage happens to be on the stack as %c.
ok thank you Eng. Corona688
the mistake was
while(EOF != (c = fgetc(filePtr)))
{
if ((c == ' ') || (c == '\n') || (c == '\0'))
{
if (c == '\0')
{
continue;
}
printf(cc); // don't assign it as string
printf("%c\n");
i=0;
memset(cc, 0, sizeof cc);
}
else
{
cc=c;
i++;
}
}
No, the wrong code is still there:
printf("%c\n"); // What will %c become? Impossible to say! Stack value roulette.
Also, your printf(cc); is wrong, because it will misbehave if cc happens to have % characters in it, which printf will take to be format specifiers.
Really, all you need is
printf("%s\n", cc);
which will do everything in 1 printf and behave.