Need Help On REG EXP in unix

Linux and Unix-Like Emergency UNIX and Linux Support
1

Respected All,

I have a very big xml in that i want to search only below 3 lines.

<target name ="UpgradePrimaryBox" depends ="configureBox1">
<echo> Finished Upgrading Primary Box </echo>
</target>

grep -i "<target.*UpgradePrimaryBox" this gives me the first line.
then i need to match second line and the </target>.

Please help me.

Thanks,
Amey

2

Hi ameyrk,

There is an option that print following lines of a match. I don't know if your version support it. Try it:

$ grep -A2 -i "<target.*UpgradePrimaryBox"

Regards,
Birei

3

Birei,

correct my version does not support.

my question is like grep -i "<target.*UpgradePrimaryBox<followed by new line><then followed by target>"

any help?

4

grep matches lines. If what you want isn't a matching line, it doesn't really do it. It's not a programming language, you can't tell it "if x, print two more lines."

awk is a programming language however. You can tell it "if x, print 2 more lines".

awk '/<target.*UpgradePrimaryBox/ { print; getline; print; getline ; print }' file
5

Wow that really worked. In this case we know there are 3 lines but if the opening and closing target are really big then any idea on that?

thanks Corona

6

If it's too big for awk on your sytem try nawk.

7

Solution to post #5:

sed -n '/<target.*UpgradePrimaryBox/,/<\/target>/p' inputfile
8 
 
$ nawk '/\<target/ , /\<\/target>/' input.txt
<target name ="UpgradePrimaryBox" depends ="configureBox1">
<echo> Finished Upgrading Primary Box </echo>
</target>