Hi,
I have file with values as below
1~ab~456~ac:bd:de:ef~yyyy-mm-dd
2~cd~458~af:fg:ty:er:ty:uj:io:~yyyy-mm-dd
I want the o/p as for frist row
1~ab~456~ac~yyyy-mm-dd
1~ab~456~bd~yyyy-mm-dd
1~ab~456~de~yyyy-mm-dd
1~ab~456~ef~yyyy-mm-dd
and for the second row
2~cd~458~af~yyyy-mm-dd
2~cd~458~fg~yyyy-mm-dd
2~cd~458~ty~yyyy-mm-dd
and so on...
So i want split the colon seperated values in rows along with other couln values..
Please help
$ cat file
1~ab~456~ac:bd:de:ef~yyyy-mm-dd
2~cd~458~af:fg:ty:er:ty:uj:io~yyyy-mm-dd
$ awk '{n = split ($4, a, ":"); for (i = 1; i <= n; i++) { print $1, $2, $3, a, $5} }' FS='~' OFS='~' file
1~ab~456~ac~yyyy-mm-dd
1~ab~456~bd~yyyy-mm-dd
1~ab~456~de~yyyy-mm-dd
1~ab~456~ef~yyyy-mm-dd
2~cd~458~af~yyyy-mm-dd
2~cd~458~fg~yyyy-mm-dd
2~cd~458~ty~yyyy-mm-dd
2~cd~458~er~yyyy-mm-dd
2~cd~458~ty~yyyy-mm-dd
2~cd~458~uj~yyyy-mm-dd
2~cd~458~io~yyyy-mm-dd
Thanks a ton!!!! It worked like magic...