Need command for date format

Shell Programming and Scripting
1

hi all,
i had a requirement in my script iam passing the parameter like (its not the system date iam passing as argument like it can be any date)

2014-08-25

but in my output file it should be

08/25/2014

please guide me

thanks in advance
hemanthsaikumar

2 
echo 2014-08-25 | awk -F '-' '{print $2, $3, $1}' OFS='/'

If you have this in a variable, say 'dt'

echo "${dt}" | awk -F '-' '{print $2, $3, $1}' OFS='/'
3

Why not adapt the script to accept your output file format?

4

hi ,
i did it by using the same awk command
its a predefined i cant change the format

14-08-25

can i get a output like

08/25/2014