Multiple variable substitutions

Shell Programming and Scripting
1

Is there anyway to accomplish this?
(ksh)

FILES_TO_PROCESS='NAME1 NAME2'

SOURCE_NAME1=/tmp/myfile
TARGET_NAME1=/somewhere/else
# other file names

for i in $FILES_TO_PROCESS
do
file1=SOURCE_$i
file2=TARGET_$i
echo cp ${$file1} ${$file2}  <-- how do get this to work.
done
2

Is it what you are trying to achieve ?

SRC=/tmp/src
DEST=/tmp/dest
for i in file1 file2
do
echo "cp $SRC/$i $DEST/$i"
done

or

... 
eval file1=\$SOURCE_$i
eval file2=\$TARGET_$i
...
eval echo "cp $file1 $file2"

eval will force the expansion of $var but not the one which is \ protected
so the finale commande after eval should look like
echo "cp $SOURCE_NAME1 $TARGET_NAME1"

Note that this would suppose that you have already setup the 2 other variables

SOURCE_NAME2=/whateverdir/whaterfile
TARGET_NAME2=/whatevernewdir/whatevernewfile

... which does not currently appear in your code

You could just copy dir

cp -p /sourcedir/* /targetdir

If you want to move them and rename them at the same time, please give us some clue about how you want them to be renamed

3

Note the trailing slash to ensure it is a dir.

(
cd /tmp/src
cp NAME1 NAME2 /tmp/dest/
)