multiple if conditions

Shell Programming and Scripting
1

Guys, Im trying to have a script that evaluates multiple conditions :

test.sh:

if [ $1 = "brazil1" ]
then
echo "host $1"
else
if [ $1 = "brazil2" ]
then
echo "host $1"
else
echo $1 not valid
exit 1
fi

when I do

 ./test.sh brazil1

I get:

./test.sh: line 12: syntax error: unexpected end of file

I'm not sure what I'm doing wrong, could you give me a hand on it please?

Thanks

2

You have two 'if' and only one 'fi' if I saw this correctly. Use the code tag.

3

Im sorry for not using the code tag, I will next time

What I'm trying to do is to have a script where I can send one parameter and based on that parameter execute a function.

if the script received brazil1 then echo something, if it receives brazil2 then echo something else.. etc.. etc..

Thanks guys, I'm sorry for the dumb question but I cant figure it out..

4

I don't see you put in the second 'fi' yet at the end so I'll change the second else to 'elif' for you:

if [ $1 = "brazil1" ]; then
   echo "host $1"
elif [ $1 = "brazil2" ]; then
   echo "host $1"
else
   echo $1 not valid
   exit 1
fi
5

I'd rather use cases, e.g.:

case $1 in
"brazil1")
  # do this
;;
"brazil2")
  # do that
;;
*)
  # oops ;-)
;;
esac

(background information)