hi i am writing a progrm to print the even numbers and the code which i am following is as follows
#!/usr/bin/bash echo "enter a number a" read a if [$a % 2 == 0] then echo "the number is even" else echo "the number is odd" fi
~ what is the mistake i am doing ...please tell me
Can you try as below. Note: Please use code tags [c ode] ... . . [/code] when posting codes,script,data etc
if [ $a%2 -eq 0 ]
When you compare values in bash use the (-eq) thing with the integers, and the (==) if you have strings...
Could be written (with arithmetic evaluation and array) #!/usr/bin/bash parity=(even odd) # parity[0]='even' parity[1]='odd' read -p "enter a number: " a echo "the number is ${parity[$((a%2))]}