Matching strings in unix shell programming

Shell Programming and Scripting
1 
 
#!bin/sh
`clear`
for i in $(seq -w 15 37);
do
#echo $i
wget --dns-timeout=0.0005 http://napdweb${i}.eao.abn-iad.ea.com:8000/webcore/test/test.jsp -o 1
A=`cat 1`
C=$(expr "$A" : '.............................................................................................................................\(......................\)')
D=": Connection timed out"
if [ "$C" = "$D" ] ;
then
echo "napdweb${i} may be hung,Please restart the server"
else
echo "napdweb${i} is up and fine "
fi
done

HI , Please see the above program.I got the output but now i have to compare the strings "C" and "D" using matching concept.Can anyone tell me how can i compare those two strings using strings matching concept.

2

you already did : if [ "$C" = "$D" ]
where ist the problem ?

3

Ya i have done it but now i have to do the matching by using regular expressions.Can anyone tell me how it can be done.

4

If you're only looking for the string "Connection timed out" then try searching your wget log file directly using grep and test the exit status of that instead.

if grep -q "Connection timed out" 1; then 
echo "napdweb${i} may be hung,Please restart the server"
else
echo "napdweb${i} is up and fine "
fi

you can ommit the A, C, and D variables and change your test as suggested.

5

I already done it by using grep command, but according to our requirement , we have to do it bu using only regular expressions.Can anyone tell me hoe it can be done by using regular expressions in unix shell programming

6

expr $c : $d

7

Read the shell manual to see what is the differences between = and == :cool:

8

I have done it by using expreesions as below

expr $C : $D

But i am getting an error as command not found.

Can anyone tell me how to match strings in the above program using shell programming