matching first instance of FS

Shell Programming and Scripting
1

Hi All,

I have a property in a file as:
property=value=a

If I use FS="=" then I want only first = to be considered as field separator and remaining as value

echo -e "property=value=a" | awk -F= '{print $2}'

ie my $2 should be value=a

Can anyone please help me with this. I need it in awk

Thanks in Advance
Guru

2 
echo  "property=value=a" | awk -F= '{print $2"="$3}'

or

echo  "property=value=a" | awk 'BEGIN{FS=OFS="="}{print $2, $3}'

Regards

3

Thanks for your reply franklin..

I am reading the properties from a file:

so there can be other files with

property=value

in this case I can't print using OFS="=" as there is no 3rd field

How to do in that case

4

In that case:

awk 'BEGIN{FS=OFS="="}{print $(NF-1), $(NF)}'

Regards