When allocating memory for two different nodes, the resulting memory are the same. Clearly, this will lead to a mistake. This happened in a function. And the process must be in a function.
(gdb) p tree->list[9]
$43 = (node *) 0x8be4180
(gdb) p tree->list[10]
$44 = (node *) 0x8be4180
At the beginning, it is correct. list[0] to list[8] is allocated properly. But it can not work well in list[9]
I very much doubt if malloc() is the problem. If you show us your code, somebody here can probably figure out what is going on.
You are right. I check the code and finally find that the error is from an assignment. but it is still strange.
list[size-2]->left = list[size-1];
the result is: list[size-2] = list[size-1];
As said before, correct before list[8] and wrong from list[9], ->left seems not to exist