ls wildcard output to a variable

I am new to shell programming, i have a requierement to assign a file name into a variable.
for ex:
the file name are below
603_2009_09_24_34.csv
702_2009_10_25_10.csv

for ex: i need to get the file 603_2009_09_24_34.csv but first 3 didgits are fixed but rest of the digits are not
below is the correct systax.?
VAR=`ls '603' * `

VAR=$(ls -1 603*)

or

VAR=`ls -1 603*`

thank you for you reply.

shall i assisn this 603 in some value i.e value='603'

VAR=`ls -1 $value*`

will work above one.?

Both will work..