Loop problem with one more problem

Shell Programming and Scripting
1

Hi ALL
I am greping some thing from a file,some thing is "/var/www/html" /var/www"/example" and so on its showing like this when u use echo.i want to pass each one of them in a loop for processing.Like start with /var/www/html then 2nd and so one
But that not working any iead how i give one by one value.
My code

docroot=$(grep -H DocumentRoot /etc/httpd/conf.d/.conf | awk -F' ' '{ print $3 }'| sort -u | uniq)
doccount=$(grep -H DocumentRoot /etc/httpd/conf.d/.conf | awk -F' ' '{ print $3 }'| sort -u | uniq | wc -l)

for (( i=0; i <= $doccount; ++i ))
do
confd="$docroot\n"
echo $confd
find $confd -type d -perm /o=w | while read DIR
do
do some thing

done ## while done
done ##for done

2

Please use English in this forum. Write "you", not "u".

What does "not working" mean? What does happen? What do you want to happen?

Please put code inside

 tags.


docroot=$(grep -H DocumentRoot /etc/httpd/conf.d/*.conf |
 awk -F' ' '{ print $3 }'| sort -u | uniq)

[/quote]

[indent]
You don't need uniq; you have already removed duplicates with sort -u.

In fact, you don't need sort, either. It can be done with awk alone:

docroot=$(grep -H DocumentRoot /etc/httpd/conf.d/*.conf |
 awk -F' ' '!x[$3]++ { ++n } END { print n }'

It is safer to stick to standard syntax:

i=0
while [ $i -le $doccount ]
do
   : whatever
   i=$(( $i + 1 ))
done

        confd="$docroot"
3

Thanks for reply,Not working means when i pass one value in loop to Variable $confd,I don't process it instead it consider online with all the document root.I show you my code,and if i run staticelly using /var/www/html output is fine but when i put
in loop problem occourced.I show you output for both.

#!/bin/bash
let test=0

abc="/var/www/html"
docroot=$(grep -H DocumentRoot /etc/httpd/conf.d/*.conf | awk -F' ' '{ print $3 }'| sort -u | uniq)
doccount=$(grep -H DocumentRoot /etc/httpd/conf.d/*.conf | awk -F' ' '{ print $3 }'| sort -u | uniq | wc -l)
#i=0
#while [ $i -le $doccount ]
# do
#    confd="$docroot\n"
#echo $confd
    find $abc -type d -perm /o=w | while read DIR
    do

    test=$(cd "$DIR"; ls -A *.html *.php  2>/dev/null | wc -l)

        if [ "$test" != "0" ]
                   then


            echo "DIR Found WITH FILES"$DIR $test
           fi


        if [ `ls -a "$DIR" | wc -l` -le 2 ]
    
                   then

            echo "Writable_dir Empty"$DIR
            fi


    done
#i=$(( $i + 1 ))
#done


        count=$(find /var/www/html/ -type f -perm /o=w | grep -i ".htaccess"| wc -l )

        find "$abc" -type f -perm /o=w | grep -i ".htaccess" | awk  -F. '{ print $1 }' | while read this

        do
        echo "_htaccess_is_Writable"$this
        done
 
Output with static docroot

DIR Found WITH FILES/var/www/html/test3 4
DIR Found WITH FILES/var/www/html/test3/abc 2
Writable_dir Empty/var/www/html/abc
DIR Found WITH FILES/var/www/html/test/abc 1
DIR Found WITH FILES/var/www/html/test2 1


Output with duynamic Docroot


"/var/www/html" "/var/www/test/www.example.com" "/var/www/www.example.com"\n
find: "/var/www: No such file or directory
find: "/var/www/test: No such file or directory
find: "/var/www: No such file or directory
"/var/www/html" "/var/www/test/www.example.com" "/var/www/www.example.com"\n
find: "/var/www: No such file or directory
find: "/var/www/test: No such file or directory
4

Your code is a little wrong there in your assigning multiple directories to the docroot and adding a newline. No need for the new line. Set confd to "$docroot" not "$docroot\n". When you do the find $confd it will put a newline in command line where it doesn't belong.

#while [ $i -le $doccount ]
# do
# confd="$docroot\n"
#echo $confd

confd="$docroot"
find $confd -type d -perm /o=w | while read DIR

which would be

find /var/www/html /var/www/test/www.example.com /var/www/www.example.com -type d -perm /o=w | while read DIR