Looking for a perl-compatible regex solution

Shell Programming and Scripting
1

This is for PHP preg_match code - which is PCRE therefore looking for a perl compatible suggestion

I have this line returned I want to match and return..

[awk -F, '(NR==2) {print $3"ABCXYZ"}' portfolio-hierarchy .csv  RootABCXYZ ^dg@torpsbe1\[1mClient_Source/20140403%

I want to match the two instances of string ending 'ABCXYZ' into an array.
And on second element (ie. RootABCXYZ) only return the word "Root"..

Thanks in advance :confused:

2

What will the actual record you want to scan look like?

3

the record is as such, i just need something that works theoretically for such, that finds the two instances of ABCD, but extract the `Root` out of ABCD......

[awk -F, '(NR==2) {print $3"ABCXYZ"}' portfolio-hierarchy .csv RootABCXYZ ^dg@torpsbe1\[1mClient_Source/20140403%

---------- Post updated at 09:45 PM ---------- Previous update was at 09:44 PM ----------

i mean ABCXYZ

4

Try this to return the value before the 2nd "ABCXYZ":

csv (.*)ABCXYZ

Match the characters "csv " literally
Match the regular expression below and capture its match into backreference number 1
   Match any single character that is not a line break character
      Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
Match the characters "ABCXYZ" literally


$result = preg_replace('/csv (.*)ABCXYZ/im', '$1', $subject);
5

Unfortunately that one is not working..
why isn't this one working either? Do you see something fundamentally wrong?

$test = "[0mawk -F, '(NR==2) {print $3"ABCXYZ"}' portfolio-hierarchy .csv  RootABCXYZ ^presales@torpsbe1\[1mClient_Source/20140403%";

preg_match('#.csv (.*?)ABCXYZ#', $test, $matches);
echo "</br>";
echo $matches[0];
echo "</br>";
echo $matches[1];

result:

(nothing)
(nothing)