Hi Guys,
Is it possible to do Logarithm of a number in Unix?? i dunno how to handl logarithm operation
assuming gnu bc:
echo "l(100)" | bc -l
l (ell) is natural logarithm.
is there any way to do log(100) which is equal to 2
not the natural logarithm. log of base 10
nevermind i got it
thanks alot for your help