List by size

Shell Programming and Scripting
1

I am trying to create a script to list files by size. I was able to show a long listing before adding parameters (first comment) but nothing seems to work after trying to add them. If the first or only parameter is -r the output should be descending order by size, if the parameter is anything else like "*.c" it should list all C programs before passing the output to the grep and sort.

The script says if found "-r" when it isn't there and vice versa and entering a star name parameter expands to the first occurrence of the specified item.

All ideas appreciated. TIA

rev=""
if [ $# -gt 0 ]
  then
  if [ $1 -eq "-r" ]
  then
    rev="-r"
    echo found -r
    shift
  fi
fi
#ls -l |grep -v "total " |sort +4n -5 +8
#ls -l $1 |grep -v "total " |sort $rev +4n -5 +8 |more -e
echo ls -l $1 grep -v "total " sort $rev +4n -5 +8 more -e
2

Try using:

ls -lrS

also:

if [ "$1" = "-r" ]

( -eq is for numerical comparisons )

1 Like
3

I couldn't get the "-lrS" to fly, but the equal sign does the trick.
Thank you.

rev=""
if [ $# -gt 0 ]
  then
  if [ $1 = '-r' ]
  then
    rev="r"
    echo $rev
    shift
  fi
fi
ls -l $* |grep -v "total " |sort +4n$rev -5 +8 |more -e