Line and word count.

Im trying to make a bash file that will take another file and count how many lines there are and then count how many words are in each line.

Any help would be great.

To calculate how many lines you can use,

wc -l filename.txt

To calulcate how many words /line,

awk '{print NR NF}' filename

sed -n '$=' filename

Thanks
Sha

Thanks, but I'm unsure as to how to go about putting this in a script.

Thanks.

seems like a home work

read about the variable assignment in shell script

Variable Assignment

Ok i have researched this a little and coming across a few problems.

1. When this code is used.

#!/bin/bash

lc=0;
el=0;

while read 
do
el= wc -w; 
lc=$(($lc+1));
echo "$el";
echo "$lc";
done < "text.txt"

Its doing a total word count and not a line by line echo with the line number then the amount of words.

2. so i tried this.

#!/bin/bash

lc=0;
el=0;

while read
do el= wc -w;
echo "$el"
done < "text.txt"

while read
do lc=$(($lc+1));
echo "$lc";
done < "text.txt"

and still the wc is not going line by line im thinking it because wc is a built in function is this correct? if so what is an alternative i can use. Also with both word counts wc -w it is skipping the first line regardless of what is in it.

Thanks

el= wc -w; 

the above will not work.

because for the wc command, you need the file name or any input

wc <options> filename

or

echo "This is test" | wc -l

and also, you need to use the backtick when you are trying to execute the command and strore the value.

eg:

count=`echo "This is the test" | wc -w`
echo $count

small correction in your script 
do el=`wc -w`;
echo $el

Try this, and also check the errors you have made.

#!/bin/bash

lc=0;
el=0;

while read line
do 
el=`echo $line|wc -w `; 
echo $el
done < "text.txt"


while read 
do 
lc=$(($lc+1));
done < "text.txt"

echo $lc;

while read
do 
el=`wc -w text.txt`
echo "$el";
done < "text.txt"

ok so i have this and it works fine. thanks for that. How would i go about the next step in getting it to word count line by line now that i have the two functions going?

Thanks

See by executing `wc -w text.txt` you are taking all word count in one go, then why are you using loop again.

maintain a variable to hold the line number and increment it each time inside the loop,
and

while read line
do
  echo $line|wc -w 
done < text.txt

this will print word count, you made the line number to it

#!/bin/bash

el=0;

while read
do 
el=`wc -l -w text.txt`
echo "$el";
done < "text.txt"

I have this code working it out puts the toal lines and total word count is there anyway to give it out line by line?

try this

 
awk '{w=w+NF};END{print "words "w"\nLine "NR}'

#!/bin/bash 
el=0;
i=1; 
while read line
do
el=`echo $line|wc -w` 
echo "LIne No. " $i ",word count" $el;
i=`expr $i + 1`
 done < text.txt

while read...
... < file
works bad when file doesn't end with newline char.

This should work:

#!/bin/sh
# Usage: count.sh FILE

wc -l <"$1"  # not print the name of FILE

DONE=false
until $DONE; do
    read s || DONE=true
    words=0
    for w in $s; do
        words=$((words+1))
    done
    echo $words
done <"$1"

./count.sh FILE | head -1

for number of lines,

count.sh FILE | tail -n+2

for numbers of words in each line.

It's, of course, easier to use awk.

I have been playing with these scripts abit to understand them but the next thing i want to do is print the lines from the file with 1 word.

would i put this in a loop and say if $el = 1 print line but i cant work out how to do this.

Thanks for all your help.