Like operator in IF statement

Shell Programming and Scripting
1

how can i use like operator in IF statement. Below is correct format, please guide

if [ $SOURCE = '*FINACLE']; then
CT_ACT_FILE_NAME=`echo FINACLE'
else
CT_ACT_FILE_NAME=`echo not listed'
fi

---------- Post updated at 04:58 PM ---------- Previous update was at 04:56 PM ----------

2

That depends on the shell you use but fail to mention.
In recent shells, the [[ ... ]] "compound command" might do what you want:

if [[ $SOURCE == *FINACLE ]]; then ...

Make sure you don't use single quotes.

3

Thanks for reply.

i have one parameter, if that parameter is like certain value than i'll execute specific command else it execute that command.

4

The reply showed the correct syntax for you to use.

Have you tried it?

Does it work?

If not, in what way did it not work?

5

Alternative in any POSIX shell

case $SOURCE in
  (*FINACLE)
    CT_ACT_FILE_NAME=FINACLE
    ;;
  (*)
    CT_ACT_FILE_NAME="not listed"
    ;;
esac

--
(or Bourne shell even)

6

I tried above way but it's not working ....

7

Moderator comments were removed during original forum migration.

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