KSH: substitution character, AWK or SED?

Shell Programming and Scripting
1

Hi Gurus,
I am working with a korn shell script. I should replace in a very great file the character ";" with a space.
Example:

2750;~
2734;~
2778;~
2751;~
2751;~
2752;~

what the fastest method is? Sed? Awk?
Speed is dead main point, Seen the dimensions of the files
Thanks

2

Try tr:

tr \; \  < infile
3 
sed 's/;/ /' infile
4

And awk.

awf -F ";"  '{print}'  infile

In my env the best was tr, then awk and last was sed.

5

are you sure this is what OP wants?

6

:). Maybe not.

awk  '{  gsub(/;/," ",$0) ;  print $0  }'  infile

And results are 1. tr, 2. sed, 3. awk

7 
awk -F\; '$1=$1' file