KSH - Find paths of multiple files in CC (dir and sub-dir))

Shell Programming and Scripting
1

Dear Members,

I have a list of xml files like

abc.xml.table
prq.xml.table
...
..
.

in a txt file.

Now I have to search the file(s) in all directories and sub-directories and print the full path of file in a output txt file.

Please help me with the script or command to do so.

Thank you very much!

2 
 
find . -type f -name "*.xml" | xargs grep -l "pattern"
3

A few questions itkamaraj

  1. The "patterns" in above command line will replace the input file in which I have the list of xml files whose path is to be found. Is that right?

  2. The output will be displayed on screen and will not be stored in a file, am I correct?

4

i misunderstood your problem.

so, you have a text file which has lot of xml files. you need to find out the absolute path of those xml files ?

 
while read filename
do
         find . -type f -name "$filename" 
done < input.txt
5

okay, sorry to bother you again, but I am a novice and have a little trouble in getting this script functional.

I created a text file filenames.txt which consists

connection_words.xml.table
da_sections.xml.table
directory_issue.xml.table
directory_section.xml.table
doc_type.xml.table

And, then I created a script search_full_path.sh like this

 #!/bin/ksh
 while read filename
do
         find . -type f -name "$filename" 
done < filenames.txt

But when I run this script I get nothing. What am I doing wrong?

6

replace the . (dot) with the path of the direcotry

 
find .

. means current directory. it will search the file from the current directory.

so replace . with the directory name which you want to search from.

1 Like
7

Thank you so much.
This works just fine!

I appreciate your patience and prompt response!

---------- Post updated at 03:08 PM ---------- Previous update was at 02:47 PM ----------

If I may, can I ask you one more question?

In all the files that I have searched along with their absolute path, there are multiple occurrences of a tag like <DmidRef RefName="GXPRODKEY"/>.

Now my question is how will I enlist all the words within double quotes (like GXPRODKEY) from among all the files that I have just searched.

8 
 
#!/bin/ksh
while read filename
do
 find . -type f -name "$filename" | xargs nawk -F"[\"=]" ' /DmidRef RefName/ {print $3}'
done < filenames.txt
1 Like
9

Awesome!
Thank man!

Can you please explain this to me
-F"[\"=]" ' /DmidRef RefName/ {print $3}'

I can understand that print $3 will return the third string/variable.

What does -F"[\"=]" do?

10

This gives clear picture for your question.

 
$ echo "A:B:C:D:E" | nawk -F: '{print $3}'     # uses :(colon) as delimeter
C

$ echo "A:B|C:D:E" | nawk -F: '{print $3}'    # uses :(colon) as delimeter
D

$ echo "A:B|C:D:E" | nawk -F"[:\|]" '{print $3}' # uses :(colon) & pipe as delimeter

C

so, in your case, i used " (double quotes) and = (equal symbol) as delimeter

1 Like
11

Great!

Thank you so much!
You made my day!

12

And this is to check whether the line has the pattern and if yes, then only print the 3rd field.

 
/DmidRef RefName/