Hello everyone,
I need help in understanding the default value for getopts option's argument in ksh. I've written a short test script:
#!/bin/ksh
usage(){
printf "Usage: -v and -m are mandatory\n\n"
}
while getopts ":v#[version:=58]m:[mirror:=ftp.tst.de]" opt; do
case $opt in
v) version="$OPTARG";;
m) mirror="$OPTARG";;
[?]) usage
exit 1 ;;
esac
done
shift $(($OPTIND - 1))
printf "version: $version\n"
printf "mirror: $mirror\n"
I'm testing the default value for getopts option's argument with the last 2 lines of the script. I was under the impression hey would have a default value if I do not specify the "-v" and "-m" option. I'm a bit confused here since I did assign a default value to each option.
I'm using KSH93 on an OpenBSD 5.8, amd64 vm.