Iteration through the results from a unix command

Shell Programming and Scripting
1

Hi,

I am using a command "ps -ef | grep identify" which results more than 1 results. Actually I need to get the time from each of them , compare with the current date and conditionally stop a process.

The problem I am facing is to iterate through the results getting from the command. Please Help me regarding this script.
Plz let me know if my problem is not clear....

Thanks
Devi

2

If you are looking for things today it won't be as easy as ps helpfully, Not, doesn't add the Month and Date to the output for processes started today .

If for earleir than today than ps -ef | grep identify | grep 'date eg Jun 11' would give you those processes. If you want to deal with them one at a time and kill them then personally I'd write them to a file, ps -ef | grep identify | grep ' Jun 11' | awk 'print $2' > pid_list.txt then using a for loop or a while loop process each and issue a kill command.

3

Thanks 4 the response.....Actually using the command " ps -ef | grep identify " gives the following result:

app 18598 17757 0 13:33 pts/1 00:00:00 grep identify
mm 34567 67444 1 12:22 pts/1 00:00:00 grep identify

I want to get one line at a time and the process further 4 the requirements......using for loop splits this line with the whitespace.

Plz help further....

thanks

4 
ps -ef | grep identify |
while read line; do
  # for example, split on whitespace once we have one line
  set -- $line
  case $5 in 13:33) echo "$@";; esac  # just as an example
done

You can use a for loop as well if you set IFS to just a newline, but while is what I would recommend.

1 Like
5

Thanks...........That solved my problem......:b: