Issues in grep command in Linux

Shell Programming and Scripting
1

Hi All

I have a file containing following records:

$HEW_TGT_DB2_USER=hbme_bi2
$prmAttunityUser=ais
$DS_USER=hbme_bi2
$prmStgUser=hbme_bi2
$prmuser=hbme_bi2
$prmStgPass=hbme_bi2
$prmpwd=hbme_bi2
$prmAttunityUser=ais

Say suppose the name of the file is test4.txt

When i fire this command on linux

ret=`grep \^$prmAttunityUser\= test4.txt`
echo $ret

The value in "ret" is blank could you all please help me in troubleshooting this where as i want that "ret" variable should contain output like this

$prmAttunityUser=ais

Thanks

2 
#ret=$(grep '$prmAttunityUser\=' test4.txt )
#echo $ret
#$prmAttunityUser=ais $prmAttunityUser=ais
3 
ret=$(grep \$prmpwd <file name>)

You need to escape $

1 Like
4

I want the output as

prmAttunityUser=ais

The output should be excluding the $ sign.

5

if you want something like

$DS_USER should be hbme_bi2
$prmAttunityUser should be ais

then you need to read about the command source or ( . )

 
$ cat test.txt
a=one
b=two
c=three
 
$ . test.txt
 
$ echo $a
one
 
$ echo $b
two
 
$ echo $c
three
6

Similar post : Grep issue

Please continue with the link ..