ip range addresses

Shell Programming and Scripting
1

I am trying to find a script that will generate all the ip addresses in particular range.

Example: start: 41.0.0.0 end ip 41.1.1.2

32.32.35.3 to 32.32.36.0

Please help.

Thanks

2

There was a recent thread about that subject here: /t/awk-print-all-ips-in-subnet/266853/1

3

awk -F. 'NR==1 {pre=$1"."$2; a=$3; d=$4} NR==2 {b=$3; c=$4} END {for(i=a;i<=b;i++) for(j=d;j<=c;j++) print pre"."i"."j}' input_file

works great if the input file is like

192.168.0.1
192.168.3.1

but my input is a bit different: 192.168.0.1 192.168.3.1

just need a little tweak for awk i guess.

Thanks

4

Hi, i modified the awk to make it more universal. It does not take netmasks into account or anything so it includes broadcast addresses for instance.

awk 'NR==1{split($1,A,".")}
     NR==2{split($1,B,".")}
     END  {for(i=A[1];i<=B[1];i++)
             for(j=A[2];j<=((i==B[1])?B[2]:255);j++)
               for(k=A[3];k<=((j==B[2])?B[3]:255);k++)
                 for(l=A[4];l<=((k==B[3])?B[4]:255);l++)
                   print i"."j"."k"."l}' infile
5

Place this awk code in a file.

BEGIN { FS="[. ]" }
END {
    a1=$1; b1=$2; c1=$3; d1=$4;
    a2=$5; b2=$6; c2=$7; d2=$8;

    while( d2 >= d1 || c2 > c1 || b2 > b1 || a2 > a1) {
       if (d1 > 255) { d1=1; c1++; }
       if (c1 > 255) { c1=1; b1++; }
       if (b1 > 255) { b1=1; a1++; }
       print a1"."b1"."c1"."d1
       d1++
    }
}

Suppose you name this file ip.awk. Then

$ echo "192.168.0.1 192.168.3.1" | awk -f ip.awk

generates an inclusive list of all IP addresses between 192.168.0.1 and 192.168.3.1, one per line.

6

super thank you.

7

Most recent Linux distro's have ipcalc that will perform this very operation. :b:

Linux Calculating Subnets with ipcalc and sipcalc Utilities

8

I don't think (s)ipcalc enumerates IP ranges, does it?

9

You are right. It does not.

10

You're correct sipcalc doesn't... still useful though.
I guess I failed to see the original focus of the question from kkkk.

Cheers!